3x^2-x+2=(x-3)(x+9)

Solution for 3x^2-x+2=(x-3)(x+9) equation:

3x^2-x+2=(x-3)(x+9)

We move all terms to the left:

3x^2-x+2-((x-3)(x+9))=0

We add all the numbers together, and all the variables

3x^2-1x-((x-3)(x+9))+2=0

We multiply parentheses ..

3x^2-((+x^2+9x-3x-27))-1x+2=0


We calculate terms in parentheses: -((+x^2+9x-3x-27)), so:

(+x^2+9x-3x-27)

We get rid of parentheses

x^2+9x-3x-27

We add all the numbers together, and all the variables

x^2+6x-27

Back to the equation:

-(x^2+6x-27)


We add all the numbers together, and all the variables

3x^2-1x-(x^2+6x-27)+2=0

We get rid of parentheses

3x^2-x^2-1x-6x+27+2=0

We add all the numbers together, and all the variables

2x^2-7x+29=0

a = 2; b = -7; c = +29;
Δ = b2-4ac
Δ = -72-4·2·29
Δ = -183
Delta is less than zero, so there is no solution for the equation